The selection committee for the Eiji Sawamura Award met today and decided to give this year's award to Hiroshima's Kenta Maeda.
For a pitcher to be considered for the award, they must meet as many of the following criteria as possible:
- fifteen or more wins
- 150 or more strikeouts
- ten or more complete games
- 2.50 or better ERA
- 200 or more innings
- twenty-five or more games
- .600 or better winning percentage
Maeda won fifteen games, struck out 175, tossed five complete games, recorded a 2.09 ERA, threw 206.1 innings, pitched in twenty-nine games, and had a winning percentage of .652. He only missed in one category, complete games. Maeda also won the award in 2010.
Hanshin's Shintaro Fujinami and Nippon Ham's Shohei Otani were also under consideration.
Selection Committee Members: Tsuneo Horiuchi (chief), Masaji Hiramatsu, Choji Murata (absent), Manabu Kitabeppu, and Hisashi Yamada.
Source: official announcement
[UPDATE 10/28 @ 9:21pm]
A little more on the selection: Horiuchi did not think it was necessary to name a recipient for the award this year. Maeda was an option, based on the number of criteria he met, but Horiuchi was not impressed with his performance, mostly because it was not much better than what he accomplished when he won the award the first time around in 2010. He felt the pitcher needed to do more to win the award a second time.
Horiuchi felt Otani had a first-half that warranted a Sawamura Award, but the second-half left a lot to be desired. Fujinami was also considered a really strong candidate with his 221 strikeouts.
Source: ZakZak 10/28/2015